Question

Three particles each of mass m are placed at the vertices of an equilateral triangle of side a the system is far from all other masses the magnitude of gravitational force acting on one of the particle is

Answer 1

Answer:

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Answer 2

Net force acting on each particle is |Fnet | = √3Gm²/a²

•Force acting on each particle is

gravitational force by two other

particles

•Net force acting on a particle is

vector sum of two forces

F1 = (Gm.m)/a² = Gm²/a² = F __(say)

F2 = (Gm.m)/a² = Gm²/a² = F__(say)

•| Fnet |² = F1² + F2² + 2F1F2Cos60°

| Fnet |² = F² + F² + 2F.FCos60°

| Fnet |² = 2F² + 2F²(1/2)

| Fnet |² = 2F² + F²

| Fnet |² = 3F²

| Fnet | = √3F

| Fnet | = √3Gm²/a²