Question

Three particles, each of mass m, are situated at the vertices of an equilateral triangle of side 'a'. The
only forces acting on the particles are their mutual gravitational forces. It is desired that each
particle moves in a circle while maintaining their original separation 'a'. Determine the initial
velocity that should be given to each particle and time period of circular motion.​

Answer 1

r=a2sec30∘=a3–√  

F=Gmma2  

F≠t=3–√F=(Gmma2)(3–√)  

 

This will provided the necassary centripetal force.  

∴mv2r=(3–√Gm2)  

T=2πrv=2π(a/3–√)Gm/a−−−−−−√=2πa33Gm−−−−−√