Three particles of equal masses are located at the vertices of an equilateral triangle where does its centre of mass lies
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The velocity of A is along AB. So, as B moves, then the direction of velocity of A changes continuously towards the direction of B.
Similarly, the velocity of B is along BC and velocity of C is along CA.
The component of velocity of B along BA = v cos60o =
So, the effective speed with which A and B approach each other
Time taken in reducing the separation AB from 'a' to zero is
Since all three particles A, B and C move with same constant speed v, hence C will also meet A and B at the same time.
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