Question

Three particles of identical masses 'm' are kept at the vertices of an equilateral triangle of each side length “a”. Find the gravitational force of attraction on any one of the particles. Need answer with solution

Answer 1

Answer:

Three identical particles each of mass m are placed at the vertices of an equilateral triangle of side a. ... So the net force on the particle P will be the force due to the particle placed at C only. ⇒F=FC=Gm. m(CP)2=Gm2(asin60)2=4Gm23a2 along PC.