three particles of mass 5g are placed at the vertices of an equilateral triangle of side 60cm find ?
distance of its center of mass from any of its vertex ??
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From symmetry, it comes that the center of mass is located at the center of circum-circle of a triangle. So, the quantity we are looking for is the radius of the circum-circle.
The formula for the circum-radius of equilateral triangle is
R = (√3/3) a .......... (1)
Where 'R' is the circum-radius and 'a' is the side length.
Given that,
a = 60 cm = 0.6 m
Put in equation (1), we get:
R = (√3/3) (0.3)
R = 0.519/3
R = 0.173 m
This is the required answer. Hopefully it is helpful to you.
Thanks.
The formula for the circum-radius of equilateral triangle is
R = (√3/3) a .......... (1)
Where 'R' is the circum-radius and 'a' is the side length.
Given that,
a = 60 cm = 0.6 m
Put in equation (1), we get:
R = (√3/3) (0.3)
R = 0.519/3
R = 0.173 m
This is the required answer. Hopefully it is helpful to you.
Thanks.
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