Physics, asked by pmanikanta0386, 4 months ago

Three particles of masses 1kg, 2kg and 2kg are placed at the corners of an equilateral triangle The co-ordinates of A,B,C are (0,0)
(2,0) and (x,y), the co-ordinates of their centre of mass are
(A
)
63
5'
(B)
6 213
5' 5
(C)
61
62
(D)
U11​

Answers

Answered by SaikiranFWS1
0

Answer:

Explanation:

xCM=m1x1+m2x2+m3x3m1+m2+m3  

       =(1)(0)+(2)(1)+(3)(0.5)1+2+3=712m

yCM=m1y1+m2y2+m3y3m1+m2+m3

       =(1)(0)+(2)(0)+(3)(3√2)1+2+3

∴d=\sqrt{x}2CM+x2CM\\

=19/√6m

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