Physics, asked by itsdummy2136, 11 months ago

Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The (x, y) coordinates of the centre of mass will be :
(A) √(3)/7 m, 7/12 m
(B) 7/12 m, √(3)/8 m
(C) √(3)/4 m, 5/12 m
(D) 7/12 m, √(3)/4 m

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Answered by Anonymous
0

Explanation:

Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The (x, y) coordinates of the centre of mass will be :

(A) √(3)/7 m, 7/12 m

(B) 7/12 m, √(3)/8 m[✓✓

(C) √(3)/4 m, 5/12 m

(D) 7/12 m, √(3)/4 m

Answered by humera98765
0

The co-ordinates of the centre of mass

rcm=3000+150×(21i^+23j^)+100×i^

rcm=127i^+43j^

∴ Co-ordinate (127,43)m

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