Question

Three particles of masses m, m and 4 kg are kept at a verticals of a triangle ABC.
Coordinates of A, B and Care (1, 2), (3, 2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m.​

Answer 1

Explanation:

refer above attachment for answer

Answer 2

The value of m is 2 kg.

Explanation:

Masses of three particles are m, m and 4 kg. Coordinates of A, B and Care (1, 2), (3, 2) and (-2,-2) respectively such that the center of mass lies at origin.

The formula of center of mass is given by :

$M_x=\dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}$

Since, $M_x=0$

$0=\dfrac{m\times 1+m\times 3+4\times (-2)}{m+m+4}$

$\dfrac{4m-8}{2m+4}=0$

On solving the above expression, we get the value of m = 2 kg

So, the value of m is 2 kg. Hence, this is the required solution.

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Center of mass

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