Three particles P. Qand Rare thrown from the top of tower with the same speed. P thrown upwards, Q horizontally and R at some angle from horizontal
They hit the ground with speed Vp, Vo and vp respectively, then (neglect air friction)
Vp=Vq=Vr
Vp<Vq>Vr
Vp<Vr<Vq
Vp>Vq>Vr
Answers
Given:
Three particles P. Qand Rare thrown from the top of tower with the same speed. P thrown upwards, Q horizontally and R at some angle from horizontal
They hit the ground with speed Vp, Vo and vp respectively
To find:
Then which option is correct?
Solution:
From given, we have,
The particle P is thrown from the top of the tower, but upwards.
The particle Q is thrown from the top of the tower, but horizontally.
The particle R is thrown from the top of the tower, but at some angle.
t{P} > t{R} > t{Q}
Speed = distance / time
speed ∝ 1/time
speed and the time are inversely proportional to each other.
As the question is all about the speed of the particles thrown upwards, horizontally and at some angle, their speed will be, Vp < Vr < Vq.
Therefore, the option Vp < Vr < Vq is correct.