Question

Three particles start from the origin at the same time, one with a velocity v1 along x-axis, the second along the y-axis with a velocity v2 and the third along x = y line. The velocity of the third so that the three may always lie on the same line is

Answer 1

Answer:

Explanation:

Break the velocity along y=x (V3) along x and y axis

therefore V3/√2=V1......along x....v3(x)=V1√2

similarily along y.....v3(y)=V2√2

therefore V3=√(2V1²+2V2²).....answer