Question

Three pendulums A, B and C have frequency 05 Hz,
0.05 Hz and 0.005 Hz respectively. The number of
oscillations completed by pendulum A and C in a
time period equal to time taken by pendulum B to
complete 200 oscillations are respectively
(1) 2000, 20
(2) 5000, 50
(3) 50, 5000
(4) 20, 2000​

Answer 1

Answer:

Option (1) 2000, 20

Step-by-step explanation:

Frequency of pendulum B = 0.05 Hz

Therefore, time period of pendulum B

$=\frac{1}{0.05}$ seconds

$=20$ seconds

i.e. in 20 seconds, pendulum B completes 1 oscillation

Therefore, it will complete 200 oscillations in 20 × 200 = 4000 seconds

Frequency of pendulum A = 0.5 Hz

Time period of pendulum A = 1/0.5 = 2 seconds

Thus in 4000 seconds, the oscillations completed by pendulum A

$=\frac{4000}{2}$

$=2000$

Frequency of pendulum C = 0.005 Hz

Time period of pendulum C = 1/0.005 = 200 seconds

Oscillations by pendulum C in 4000 seconds

$=\frac{4000}{200}$

$=20$

Hope this helps.