Three people a b and c are standing in queue. There are 5 people between a and b, and 8 people between b and c. If there be 3 people ahead of c and 21 people behind ma .what could be the minimum ni of people in queue
Ans
Three person C A B
Total person= 3+1+8+1+5+21
= 40
Second condition is
People between a and c= 8-6
= 2
Minimum people = 3+1+2+1+21
= 21
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Answer:
Three person C A B
Total person= 3+1+8+1+5+21
= 40
Second condition is
People between a and c= 8-6
= 2
Minimum people = 3+1+2+1+21
= 21
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