Three people,A, B and C participate in a race. It is known that A runs the fastest followed by B followed by C. The distance over which they race is 100 meters. If A and B were to finish the race at the same time, A would start when B reaches the 10 metersmark. Similarly, if A and C were to finish the race at the same time, A would start when C reaches the 28 metersmark. If B and C were racing, how much of a distance should C run before B starts so as to ensure that they finish at the same time
Answers
Lets say distance is 100 mtr
Time taken by A = 60 second
Since A defeated B by 10 meter.. so when A was crossing the win line B covered(100-10 = 90 meter).
So B took 60 second to cover 90 meter.
Time taken by B to reach win line or time taken by B to cover 100 meter:
(60/90)*100 = 66.6 second
So B took 66.6 to reach winning line.
So while B was crossing win line on 66.6th second C covered 90 meter(100-90 second)
Time taken by C to reach win line or time taken by C to cover 100 meter:
(66.6/90)*100 = 74.04 second
Since all player are running with same speed.
Now we have time taken my each player to cover 100 meter.
Distance with which A defeated C is equal
(Distance of A in 60 second) - (distance of C in 60 second) = 100 - (100*60/74.04) = 100-81.03 = 18.96 meter
So exact answer is 18.96 meter.
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