Three perfect gases at absolute temprature T₁ T₂ and T₃ are mixed. The masses of molecules are m₁ , m₂ and m₃ and the number of molecules are n₁ , n₂ and n₃ respectively . Assuming no loss of energy, the final temprature of the mixture is [ AIEEE 2011]
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Explanation :- For perfect kinetc energy = F/2nkt
∴ sum of each gaseous kE = F/2n₁ kT₁ + F/2n₂kT₂ = F/2 n₃ kT₃
⟹ F/2(n₁+n₂ + n₃)kT [∵ F is degree of freedom ]
Total kinetic energy = F/2(n₁ +n₂+n₃)kT
∵ sum of each gaseous k.E = total KE
temprature of mixture
- ∴ T= n₁T₁ + n₂T₂ + n₃T₃ /n₁ +n₂+n₃ Answer
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