Question

Three perfect gases at absolute temprature T₁ T₂ and T₃ are mixed. The masses of molecules are m₁ , m₂ and m₃ and the number of molecules are n₁ , n₂ and n₃ respectively . Assuming no loss of energy, the final temprature of the mixture is [ AIEEE 2011]​

Answer 1

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Answer 2

Explanation :- For perfect kinetc energy = F/2nkt

∴ sum of each gaseous kE = F/2n₁ kT₁ + F/2n₂kT₂ = F/2 n₃ kT₃

⟹ F/2(n₁+n₂ + n₃)kT [∵ F is degree of freedom ]

Total kinetic energy = F/2(n₁ +n₂+n₃)kT

∵ sum of each gaseous k.E = total KE

temprature of mixture

• ∴ T= n₁T₁ + n₂T₂ + n₃T₃ /n₁ +n₂+n₃ Answer