Three person complete half of a work in 8 days if one of them discontinued working how many days would they take to do the remaining half
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3 person complete 1/2 work in 8 days and full work in 16 days.
work done by 1 person in 1 day = 1/ ( 16 x 3 ) = 1/ 48.
work done by 2 person in 1 day = 1/ 24.
Time taken by 2 person to do full work is 24 days and 1/2 work is 12 days.
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From the given question given to us,
Let us assume the total work to be x
Total work done by 3 people in 8 days is x/2
Total work done by 1 man in 1 day is equal to x/48
The one man leaves. The total work done by him is x/6(x/48*8)
Therefore the time required to complete the remaining work by 7 people is
X/6 + X/48 ×t + X/48 ×t = X
Once we solve this we get the answer to be 20 days.
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