Three persons A, B and C at the corners of an equilateral triangle of side 'x' move at a constant speed v'. Each person maintains a direction towards the person at the next corner.The time, the persons will take to meet each other is
1)2x/3v
2)2x/v
3)X/v
4)4x/3v
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Answer:
Explanation:
When A starts moving towards B, B has already started moving towards C and as B starts moving towards C, C has already started moving towards A, and as C starts moving towards A , A has already started moving towards B.
velocity of A is V along AB
the velocity of B is along BC . its component along BA is Vcos60= V/2 . thus the separation AB decreases at the rate V res
=V+ V/2=3V/2
since this rate is constant. the time taken in reducing the separation AB from X to 0 is
time=Distance/Speed=X/3V/2
=2X/3V
Therefore option [1] is correct
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