Three persons, A, B and C, fire at a target in turn, starting with A. Their probability of hitting the target are 0.4, 0.3 and 0.2 respectively. Find the probability of two hits.
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Answer: The possibility for person a is 0.16, the possibility of person b is 0.09, and the possibility of person c is 0.04
Step-by-step explanation: You use the first possibility and then multiply it to the 2nd power
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