Three persons A, B and C working separately can do a work in 3, 7 and 5 days respectively.
If they all work together and earn 4615 for the whole work, how much will each of
them get?
Answers
As the work in different proportion thus the amount division is like,
Let total work is W,
So work by A per day = W/A = W/3
Work by B per day = W/B = W/7
Work by C per day = W/C = W/5
So proportion of A,B&C get paid,
Amount of A = 4615*(W/A)/ { (W/A) +(W/B) + (W/C) }
= 4615*(W/3)/{ (W/3) + (W/7) + (W/5) }
= 4615*35/( 35 + 15 + 21 )
= 4615*35/71
= 2275
Amount of B = 4615*(W/B)/ { (W/A) +(W/B) + (W/C) }
= 4615*(W/7)/{ (W/3) + (W/7) + (W/5) }
= 4615*15/( 35 + 15 + 21 )
= 4615*15/71
= 975
Amount of C = 4615*(W/C)/ { (W/A) +(W/B) + (W/C) }
= 4615*(W/5)/{ (W/3) + (W/7) + (W/5) }
= 4615*21/( 35 + 15 + 21 )
= 4615*21/71
= 1365
Amount(A) = 4615/3 = Rs 2275
Amount(A) = 4615/3 = Rs 2275Amount(B) = 4615/7 = Rs 975
Amount(A) = 4615/3 = Rs 2275Amount(B) = 4615/7 = Rs 975Amount(C) = 4615/5 = Rs 1365
Hope it may help you!
Answer:
As the work in different proportion thus the amount division is like,
Let total work is W,
So work by A per day = W/A = W/3
Work by B per day = W/B = W/7
Work by C per day = W/C = W/5
So proportion of A,B&C get paid,
Amount of A = 4615*(W/A)/ { (W/A) +(W/B) + (W/C) }
= 4615*(W/3)/{ (W/3) + (W/7) + (W/5) }
= 4615*35/( 35 + 15 + 21 )
= 4615*35/71
= 2275
Amount of B = 4615*(W/B)/ { (W/A) +(W/B) + (W/C) }
= 4615*(W/7)/{ (W/3) + (W/7) + (W/5) }
= 4615*15/( 35 + 15 + 21 )
= 4615*15/71
= 975
Amount of C = 4615*(W/C)/ { (W/A) +(W/B) + (W/C) }
= 4615*(W/5)/{ (W/3) + (W/7) + (W/5) }
= 4615*21/( 35 + 15 + 21 )
= 4615*21/71
= 1365
Amount(A) = 4615/3 = Rs 2275
Amount(B) = 4615/7 = Rs 975
Amount(C) = 4615/5 = Rs 1365
Hope it may help you!