Math, asked by drashti432003, 6 hours ago

Three persons A,B,C aim a target. The probability of hitting the target are 1/3, ½, and 2/5 respectively . The probability that the target will not be hit is

Answers

Answered by yashbhowmik99
0

Answer:

0.2

Step-by-step explanation:

P(A) = 1/3

P(B) = 1/2

P(C) = 2/5

So, P(A')= 1-P(A) = 1-1/3 = 2/3

Here A' denotes the event that A will not hit the target.

Similarly P(B') = 1/2

And, P(C') = 3/5

So, the target will not be hit when all three will miss the target.

P(target will not be hit) = P( A'^B'^C') = P(A')*P(B')*P(C') = (2/3)*(1/2)*(3/5) = 1/5 = 0.2

As all the events are independent so their probabilities are multiplied

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