three persons boarded a bus in which 5seats are vacant. In how many different ways can they sit?
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Clearly, the first person can occupy any of the 5 seats.
So, there are 5 ways in which the first person can seat himself.
Now, the second person can occupy any of the remaining 4 seats.
So, the second person can be seated in 4 ways.
Similarly, the third person can occupy a seat in 3 ways.
Hence, by the fundamental principle of multiplication, the required number of ways =(5×4×3)=60 ways
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