Question

Three persons named John David and
Robert are hired to complete a work.
John alone takes 8days David alone takes
12 days and Roberts alone takes 16 days
to complete to start with John works for
2 days and then replaced by David. David
works for 3 days and replaced by Roberts
to complete the remaining. If the yiatl
wages of John David and Robert is 3000
the find John's wages for his work
11:06​

Answer 1

Given :- Three persons named John David and Robert are hired to complete a work. John alone takes 8 days David alone takes 12 days and Roberts alone takes 16 days to complete the work . Start with John works for 2 days and then replaced by David. David works for 3 days and replaced by Roberts to complete the remaining. If the total

wages of John David and Robert is 3000 the find John's wages for his work ?

Answer :-

→ LCM of 8, 12 and 16 = 48 units = Let total work .

so,

→ Efficiency of John = Total work / time taken = 48/8 = 6 units / day .

→ Efficiency of David = Total work / time taken = 48/12 = 4 units / day .

→ Efficiency of Robert = Total work / time taken = 48/16 = 3 units / day .

then,

→ In first 2 days John did = 2 * 6 = 12 units of work .

→ In next 3 days David did = 3 * 4 = 12 units of work .

So,

→ Left work to be done by Robert now = 48 - (12 + 12) = 24 units .

therefore,

→ Share of John : David : Robert = 12 : 12 : 24 = 1 : 1 : 2 .

hence,

→ wages of John = 3000 * (1/4) = Rs.750 (Ans.)

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