Question

three pieces of timber 42m,49m,63m long have to be divided into planks ofthe same length what is the greatest possible length of each planks how many planks are formed

Answer 1

HCF of 42,49,63 = 7


1st plank i.e 42/7 = 6

2nd plank i.e 49/7 = 7

3rd plank i.e 63/7 = 9


Planks formed are = 6 + 7 + 9

                                = 22


Hope this helps!

Answer 2

Hello friend
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First we will FIND HCF of 42,49 and 63 which is 7

Now ,

dividing all three pieces by 7 , we get

1st piece- 42/ 7 = 6

2nd piece- 49/7 = 7

3rd piece- 63/7 = 9

Now, adding the sums of three pieces , we get

6+7+9 = 22
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Hope it will help u