Question

Three pieces of timber 42m,49m,63m long have to be divided into planks ofthe same length what is the greatest possible length of each planks how many planks

Answer 1

Given :

• Three pieces of timber 42m,49m,63m long have to be divided into planks ofthe same length.

To find :

• The greatest possible length of each planks and how many planks =?

Step-by-step explanation :

Dimensions of the three pieces of timber 42m,49m,63m.

Now,

We have to find the greatest possible length of each planks, So firstly find the HCF (Highest Common Factor) of dimensions of the three pieces of timber.

H. C. F of 42, 49 amd 63 :-

42 = 2 × 3 × 7

49 = 7 × 7

63 = 3 × 3 × 7

•°• HCF = 7.

Therefore, 7 is the greatest possible length of each planks.

Now,

The number of planks,

42/7 = 6

49/7 = 7

63/7 = 9

Adding each planks, we get,

= 6 + 7 + 9

= 22

Therefore, 22 Planks in the total three pieces timber.

Answer 2

Dimensions of the three pieces of timber 42m,49m,63m.

Now,

We have to find the greatest possible length of each planks, So firstly find the HCF (Highest Common Factor) of dimensions of the three pieces of timber.

H. C. F of 42, 49 amd 63 :-

42 = 2 × 3 × 7

49 = 7 × 7

63 = 3 × 3 × 7

•°• HCF = 7.

Therefore, 7 is the greatest possible length of each planks.

Now,

The number of planks,

42/7 = 6

49/7 = 7

63/7 = 9

Adding each planks, we get,

= 6 + 7 + 9

= 22

Therefore, 22 Planks in the total three pieces timber.