Question

three pieces of timber 42m ,49m,ad 63m long, have to be divided into planks of the same length . what is the greatest possible length of each plank ?​

Answer 1

Answer:

7m

Step-by-step explanation:

Given : the lengths of three pieces of timber are 42 m,49 m and 63 m respectively. we have to divide the timber into equal length of planks.

Greatest possible length of each plank =HCF(42,49,63)

The prime factorization of 42,49 and 63 are:

42=2×3×7

49=7×7

63=3×3×7

HCF (42,49,63)=7

The greatest possible length of each plank is 7 m.

Again, the number of planks can be formed =22.

Answer 2

Answer:

answer is 22

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