Question

Three pieces of timber 42m,49m and 56 m lone have to be divided into planks of the same length.what is the greatest possible length of each plank

Answer 1

Hey!!!!

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Here the greatest possible length of each plank

=> Each Plank/HCF(42,49,56)

Thus By Prime Factorisation Method

=> 42 = 2 x 3 x 7

=> 49 = 7²

=> 56 = 2³ x 7

Thus HCF = 7

For Each

=> 42/7 = 6

=> 49/7 = 7

=> 56/7 = 8

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Hope this helps ✌️

Legally Good Morning :)

Answer 2

SOLUTION :-

GIVEN 》

Three pieces of timber = 42m, 49m,56m

greatest possible length of each plank = ?

divided into planks of the same length.=?

take HCF,

42 = 2×3×7
49= 7×7
56= 2×2×7

HCF = 7

(divided into planks of the same length = 7m )

= 42/7 = 6

= 49/7 = 7

= 56/7 = 8

(greatest possible length of each plank= 6m, 7m,8m ) ans
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