Question

Three pieces of timber 48m,64m and 96m have to be divided in to planks of same length. What is the greatest possible length of each plank?​

Answer 1

Answer:

The lengths of three pieces of timber are 48m, 64m and 96m respectively. 

We have to divide the timber into equal length of planks. 

∴ Greatest possible length of each plank = HCF ( 48,64,96)

Prime factorization:

48-2×2×2×2×3

64-2×2×2×2×2×2

96-2 × 2 × 2 × 2 × 2 × 3 

∴HCF = Product of the smallest power of each common prime factor involved in the numbers = 16

Hence, the greatest possible length of each plank is 16m.

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Answer 2

Answer:

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