Three pipes a, b and c are attached to a cistern pipe. a and b can fill it in 30 hours and 20 hours respectively, and third pipe c can leaks out 15 litre water/minute. if all the three pipes are opened simultaneously the cistern will be filled in 15 hours. find the capacity of the cistern.,
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part filled by pipe A in 1 hour =15
part filled by pipe B in 1 hour = 16
Pipe C can empty the tank in 12 hours. Therefore,
part emptied by pipe C in 1 hour =112
Net part filled by Pipes A,B,C together in 1 hour
=15+16−112=1760
i.e., the tank can be filled in 6017=3917
part filled by pipe B in 1 hour = 16
Pipe C can empty the tank in 12 hours. Therefore,
part emptied by pipe C in 1 hour =112
Net part filled by Pipes A,B,C together in 1 hour
=15+16−112=1760
i.e., the tank can be filled in 6017=3917
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