Three pipes A, B and C are connected to a tank. A and B together can fill a tank in 60 minutes, B and C together in 40 minutes and C and A together in 30minutes. In how much time will each pipe fill the tank separately?
Answers
Answer:
Part of tank filled by A in 1 min = 1/60
Part of tank filled by B in 1 min.= 1/45
Part of tank filled by both A and B together
= 1/60 + 1/45 = (3+4)/180 = 7/180
Part of the tank emptied by C in 1 min = 1/30
Part of tank filled if all 3 pipes are opened in 1 min.
= 7/180 — 1/30 = (7–6)/180 = 1/180
So if all the three pipes are opened time taken to fill the tank = 180 min = 3 he's.
Explanation:
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Answer:
Part of tank filled by A in 1 min = 1/60
Part of tank filled by B in 1 min.= 1/45
Part of tank filled by both A and B together
= 1/60 + 1/45 = (3+4)/180 = 7/180
Part of the tank emptied by C in 1 min = 1/30
Part of tank filled if all 3 pipes are opened in 1 min.
= 7/180 — 1/30 = (7–6)/180 = 1/180
So if all the three pipes are opened time taken to fill the tank = 180 min = 3 he's.