Three pipes A, B and C can fill a cistern in 4, 8 and
12 hours respectively, while another pipe D can alone
empty it in 10 hours. Then which of the following
arrangements will fill the cistern in the least possible
time?
Answers
Answered by
0
Answer:
Total time required to fill the cistern for unit =1/4+1/8+1/12-1/10
=43/120
Total time required=120/43 hr
Similar questions