Math, asked by shivamk4638, 5 months ago

Three pipes A, B and C can fill a cistern in 4, 8 and
12 hours respectively, while another pipe D can alone
empty it in 10 hours. Then which of the following
arrangements will fill the cistern in the least possible
time?

Answers

Answered by tajnemahendra

0

Answer:

Total time required to fill the cistern for unit =1/4+1/8+1/12-1/10

=43/120

Total time required=120/43 hr

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