Question

Three pipes A, B and C can fill a tank in 12 hours, 15 hours and 20 hours respectively. How long wou
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the three pipes take to fill the empty tank , if all the taps are opened together​

Answer 1

Answer:

5 hours

Step-by-step explanation:

Three pipes A,B, and C can fill tank in 12hrs, 15hrs and 20hrs.

therefore, part of tank filled by pipe A in 1hr = $\frac{1}{12}$

                 part of tank filled by pipe B in 1hr = $\frac{1}{20}$

                 part of tank filled by pipe C in 1hr = $\frac{1}{20}$

therefore, If all pipes ,i.e, A B and C are opened together

                 part of tank filled in 1hr =$\frac{1}{12} + \frac{1}{15} + \frac{1}{20} = \frac{12}{60} = \frac{1}{5}$

Hence, It will take 5 hours to fill the tank if all the three pipes are opened