Three pipes a , b and c can fill a tank in 6 hours , after working it at together for 2 hours , c is closed and a and b can fill the remaining part in 7 hours . How much time will c take alone to fill the tank
Answers
Answered by
0
ans =14 hours
explanation:
Part filled in 2 hours = 2 = 1
6 3
Remaining part = 1 - 1 = 2 .
3 3
(A + B)'s 7 hour's work = 2
3
(A + B)'s 1 hour's work = 2
21
C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }
= 1 - 2 = 1
6 21 14
hence C alone can fill the tank in 14 hours.
Similar questions