Math, asked by satya0218, 9 months ago

Three pipes A, B and C can fill a tank in 6 hrs . After working at it together for 2 hrs C is closed

and A and B can fill the remaining part in 7 hrs . The total number of hrs taken by C alone to fill the

tank is​

Answers

Answered by farcastikfaraz
3

Answer:14 hours. Bro please mark brainliest.

Step-by-step explanation:

In two hours the tank is filled \frac{2}{6} of it's total capacity.

for filling the remaining 2/3 tank A and B take 7 hours.

Let us see ow much both A and B fill in 1 hour.

They fill 2/3*1/7 = 2/21 of the total capacity.

Whereas with C they were able to fill 1/6 of the tank.

then the amount of capacity that C fills in 1 hour will be

1/6 - 2/21 =3/42

3/42 in 1 hour therefore C will take 14 hours to fill the tank alone.

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