Question

three pipes A,B and C can fill an empty tank in 4hours,5hours and 6hours respectively. there is a hole in the tank which can empty a full tank in 8 hours. initially, the tank is empty. A and B are opend. They are closed half an hour. C is opend and allowed to run for next 1 hour. then, find the total time required to fill the tank if all the three taps are opend simultaneously after the first one and a half hour.​

Answer 1

Step-by-step explanation:

Answer

Let the tank be full in x min. Then,

6x+8x+12x−4=1

⇒244x+3x+2(x−4)=1

⇒9x−8=24

⇒9x=32⇒x=395 min.