Three pipes a b c can fill a tank in 300 minutes 480 minutes and 420 minutes
Answers
If you are asking in how much time they can fill the tank if they are operated together, here's your answer:
You can convert minutes into hours so the time taken in hours by all pipes will be:
Pipe A= 5 hours
Pipe B= 8 hours
Pipe C= 7 hours
Let's assume total work as 280 units (because it can be easily cancelled by 5,8 and 7)
Then rate of work for Pipes a,b and c will be:
Pipe A= 280/5= 56
Pipe B= 280/8= 35
Pipe C= 280/7= 40
Total capacity= 56+35+40 =131
So time taken by A+B+C= 280/131
= 2.13 hours or 2 hours and 8 minutes or 128 minutes
Given : Three pipes A, B & C can fill a tank in 300 min, 480 min & 420 respectively
all the pipes are opened simultaneously
To Find : how long will it take for the tank to get full
Solution:
pipe A fill in1 min= 1/300
pipe B fill in 1 min = 1/480
pipe C fill in 1 min = 1/420
All together fill in 1 min = 1/300 + 1/480 + 1/420
= (1/60) ( 1/5 + 1/8 + 1/7)
= (1/60) ( 56 + 35 + 40) /280
= (1/ 16800) (131)
Time taken to fill tank = 16800/131
=128.24
= 128 mins
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