three pipes a,b,c can fill tank in 8 hr. after working at it for 2 hr a is closed and b,c fill the tank in 9 hr. what is the number of hours taken to fill the cistern by a
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Answer:Part filled in 2 hours = 2/6 = 1/3. Remaining part = 2/3
(A + B)'s 7 hours' work = 2/3.
So, (A+B)'s 1 hr work = 2/21
Therefore C's 1 hour's work
= [(A+B+C)'s 1 hour]-[(A+B)'s 1 hr work]
=(1/6 - 2/21) = 1/14
C alone can fill the tank in 14 hours
Option 5)
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