three pipes can fill a tank in 10 minutes the first 5 by itself can fill it in 30 minutes and the second pi by itself in 25 minutes in what time will the third pipe fill the tank
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Answer:
37.5 mins
Step-by-step explanation:
Total time taken by 1st pipe alone = a
Total time taken by 2nd pipe alone = b
Total time taken by 3rd pipe alone = c
Let 1/a be the work done by 1st pipe in 1 min , 1/b for the 2nd pipe and 1/c for the 3rd pipe..
Total Time taken by all 3 pipes to fill the tank = 10mins
Work done in 1 min = 1/10
According to Question:
1/a + 1/b + 1/c = 1/10 --------- 1st equation
a = 30
b= 25
Substitute both in 1st Equation
= 1/30 + 1/25 + 1/c = 1/10
After taking L.C.M.
= (5 + 6)/150 + 1/c = 1/10
1/c = 1/10 - 11/150
1/c = (15 - 11)/150
1/c = 4/150
c = 150/4
= 37.5 mins
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