Question

Three point charge q_1=1muC, q_2=-2muC and q_3=3muC are placed at (1m, 0,0), (0,2m,0) and (0,0,3m) respectively. Find the electric potential at as origin.

Answer 1

Answer:

HELLO!

Explanation:

The net electric potential at origin is, Substituting the values,

three-point-charges-q1-1c-q2-2c-and-q3-3c-are-placed-at-1m-0-0-0-2m-0-and-0-0-3m

Answer 2

Given :

• q₁ = 1 μC placed at (1m , 0 , 0)
• q₂ = -2 μC placed at (0 , 2m , 0)
• q₃ = 3 μC placed at (0 , 0 , 3m)

To find :

• Electric potential(V) at origin.  

Solution :

• The distances of the charges q₁, q₂ and q₃ from the origin are 1m , 2m and 3m respectively. We can tell this by looking at the co-ordinates.
• We know that, electric potential due to a charge q at a distance r is given by :

        V = (1/4πε₀)(q/r)

• Hence, the net potential due to the three charges will be :

        V = (1/4πε₀)(q₁/r₁) + (1/4πε₀)(q₂/r₂) + (1/4πε₀)(q₃/r₃)

            = (1/4πε₀) [(q₁/r₁) + (q₂/r₂) + (q₃/r₃) ]

            = (1/4πε₀) [$\frac{1 . 10^{-6} }{1}$ - $\frac{2 . 10^{-6} }{2}$ + $\frac{3 . 10^{-6} }{3}$]

            = 9 × 10⁹× 10⁻⁶ [ 1 - 1 + 1]          ....(∵ (1/4πε₀) = 9 × 10⁹ N/C )

         V = 9 × 10³ V

Answer:

The potential at the origin is 9000 V.