three point charges 10 microcoulomb and 10 microcoulomb and minus 10 microcoulomb are placed at three corners of an equilateral triangle each of side 10cm find the net force experienced by the charges 10 microcoulomb and -10 microcoulomb
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Take both the 2q charges at the centre of the line and now it's a ± 4q dipole of length x√3/4. Dipole moment is hence xq√3.
Edit 1.
Actually, that's a wrong approach. Take -4q charge as two -2q charge. And then you have two dipoles of ±2q charge of x length placed at each other at 60° angle.
Basically net dipole moment will be vector addition of two dipoles of dipole moment 2qx at 60° each. Which should be 4qx/√3.
Edit 1.
Actually, that's a wrong approach. Take -4q charge as two -2q charge. And then you have two dipoles of ±2q charge of x length placed at each other at 60° angle.
Basically net dipole moment will be vector addition of two dipoles of dipole moment 2qx at 60° each. Which should be 4qx/√3.
parthasarathi46:
this is not currect
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