Question

three point charges 2 microcoulomb - 4 microcoulomb and 8 my microcoulombs Always At the three vertices of a equilateral triangle or whose side is length 10 centimetre the potential at the centre of the triangle​

Answer 1

Three point charges of 2μC , −4μC and 8μC are placed at three vertices of an equilateral triangle of side length 10cm.

we have to find potential at the centre of triangle.

first find distance between charges and centre of triangle.i.e., OA , OB and OC

OA = OB = OC = $\frac{2}{3}\sqrt{(10)^2-5^2}=\frac{2}{3}5\sqrt{3}=\frac{10}{\sqrt{3}}cm$

now potential at the centre of triangle , V = $\frac{Kq_A}{OA}+\frac{kq_B}{OB}+\frac{kq_C}{OC}$

=$\frac{\sqrt{3}k(2\mu C)}{10cm}+\frac{\sqrt{3}k(-4\mu C)}{10cm}+\frac{\sqrt{3}k(8\mu C)}{10cm}$

= $\frac{6\mu C\sqrt{3}k}{10cm}$

= 6 × 10^-6 × 1.732 × 9 × 10^9/(0.1)

= 54 × 1.732 × 10³ N/C

= 93.528 × 10³ N/C

= 9.3528 × 10⁴ N/C