Question

Three-point charges are fixed in a straight line. The quantities of charges on each are Q1 = 4.0 × 10 -6 C, Q 2 = 1.0 × 10 - 6 C and Q 3 = -5.0 × 10 - 6 C respectively. The distance between Q1 and Q2 is 4.0 cm and the distance between Q 2 and Q 3 is 3.0 cm. What is the approximate force on Q 2 due to the other two charges?

Answer 1

Explanation:

i think

answer is 40cm

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