Three point charges each of value + q coulomb are placed on three vertices of a square of side l metre. Find the magnitude of force on the charge - q coulomb placed at the centre of square.
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Answer:2kq²
Explanation:the resultant force due to the two opposite vertices will get cancelled so the charge placed at the centre will experience an attractive force (being opposite in nature) due to the remaining charge. So by the formula, F= kq1q2/r², where r= √2/2= 1/√2 metres, we get force = 2kq²
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