Question

Three point mass 100g, 200g and 300g are placed at the vertices of an equilateral triangle of side 10 cm. Find the coordinate of centre of mass of the system (3)​

Answer 1

Answer:

0.2 cm

Explanation:

Given that,

 m  

1

​

=100g

m  

2

​

=150g

m  

3

​

=200g

a = 0.5 m = 50 cm

Now, according to diagram

Center of mass coordinates

 X  

cm

​

=  

450

0×100+150×50+200×25

​

 

X  

cm

​

=  

450

7500+5000

​

 

X  

cm

​

=27.8cm

X  

cm

​

=0.28m

Now,

 Y  

cm

​

=  

450

0×100+0×150+  

3

​

×25×200

​

 

Y  

cm

​

=  

450

8660.3

​

 

Y  

cm

​

=19.2cm

Y  

cm

​

=0.2m

Hence, the center of mass of three particles at the vertices of an equilateral triangle is X  

cm

​

=0.28cm and Y  

cm

​

=0.2cm  respectively