Physics, asked by bharath691489, 6 months ago

three point masses 3kg, 2kg, 1kg are placed at a,b,c of a triangle ab=0.3,ac =0.5,bc=0.4m the mi of the systematic about an axis through a and normal to the plane of triangle is​

Answers

Answered by userg4470
2

Answer:

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The moment of inertia of a point mass about an axis is given by:

I=Mr

2

(Where r= perpendicular distance of point mass from the axis)

Here axis passes through A and is at distances 0.3m and 0.5m from 2 kg and 1 kg mass respectively.

So net moment of inertia (I

net

)=3×0

2

+2×0.3

2

+1×0.5

2

=0.18+0.25

⇒I

net

=0.43 kg-m

2

.

l

AB = 0.3m, AC = 0.5m and BC = 0.4m. the M.I of the system about an axis through A and normal to the plane of triangle is? (ans : 0.43km2

Answered by ItzWanderousGirl
6

Answer:

ǟɮ =0.3ʍ

ǟƈ= 0.5ʍ

ɮƈ => 0.4

Explanation:

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