Question

three point masses each of mass M are placed that ends of equilateral triangle of side a the moment of inertia of the system about an Axis passes through centre of mass and perpendicular to plane will be ​

Answer 1

Answer:

: Moment of inertia is (3ml^2)/4

Explanation:

Before looking this calculation please have a look on the attached pic which will clear you the idea about situation and different parameters .

Moment of inertia is ;

I = mr^2……………..eq 1

Now we need to find radius; this has been shown in figure;

As this is an equilateral triangle with all the 3 sides equal to l;

So applying Pythagoras theorem;

L^2 = (l/2)^2 + r^2

R= (√3l)/2

Putting value of R^2 in eq 1;

I = m(3l^2)/4 which is the answer