three point masses of 1g 2g and 3g lie in the X-Y plane at respective points (1 ,2),(0,-1)and (2,-3). find the coordinate of the center of mass of the system
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m₁ = 1 g , x₁ = 1 , y₁ = 2
m₂ = 2 g , x₂ = 0 , y₂ = - 1
m₃ = 3 g , x₃ = 2 , y₃ = -3
x-coordinate of center of mass is given as
x = (m₁ x₁ + m₂ x₂ + m₃ x₃ )/(m₁ + m₂ + m₃)
x = ((1) (1) + (2) (0) + (3) (2) )/(1 + 2 + 3) = 1.2
y-coordinate of center of mass is given as
y = (m₁ y₁ + m₂ y₂ + m₃ y₃ )/(m₁ + m₂ + m₃)
y = ((1) (2) + (2) (-1) + (3) (-3) )/(1 + 2 + 3) = - 1.5
so coordinate of center of mass is (1.2 , - 1.5)
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Answer:
Answer is 7/6,-3/2
I hope it helps you.
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