Question

Three points A, B and C are located on a circle which are equidistant from one another. If the radius of the circle is 20m the calculate the length of AB​

Answer 1

Answer:

OS=r=20m.

Step-by-step explanation:

The boys are sitting at an equal distance. Hence, △ASD is an equilateral triangle. Let the radius of the circular park be r meters. ∴OS=r=20m.

Answer 2

Answer:

Let A,B and C be three non-collinear points

Join AB and BC

Draw perpendicular bisector of AB and BC

Let them meet at point O

Then O lie on the right bisector of AB

So, OA=OB

And O lies on the right bisector of BC

So, OB=OC

Hence, the point O is equidistant from A,B and C.

Now since the right bisector of AB and BC are non-parallel lines, therefore they have only one point in common.

So, O is the only point equidistant from A,B and C.

Hence, the required locus is the centre of the circle through the given non-collinear points.

Step-by-step explanation:

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