Three points on the ground form an equilateral triangle. There is a vertical pillar at
A
. The angle of elevation of the top of the pillar is 53° from the midpoint of BC and theta° from the midpoint of AB. Find tan theta
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Given:
Three points on the ground form an equilateral triangle.
Points be A, B and C.
There is a vertical pillar at A.
The angle of elevation of the top of the pillar is 53° from the midpoint of BC.
The angle of elevation of the top of the pillar is Ф° from the midpoint of AB.
To Find:
tan Ф
Solution:
Let D be the mid point of BC.
E be the midpoint of AB.
Let Q be the top point of the pillar.
If m is the altitude of the triangle ΔABC ,
- m = AD
- m =√ a² - (a/2)² = a√3/2
Consider ΔDAQ,
- tan 53° = AQ/AD = h/m = 2h/a√3
- 2h/a√3 = 4/3
- h = 2a/√3
Now consider ΔEAQ,
- tan Ф = h/AE = (2a/√3)/ a/2 = 4/√3
Therefore,
The value of tan Ф = 4/√3.
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