Question

Three positive numbers are in the ratio 7:3:2. The sum of the smallest number and the largest number exceeds twice the remaining number by 30. Find the three numbers.

Answer 1

Answer: The three numbers are 20,30, and 70,


Step-by-step explanation:

There you go I gave you the answer no need for an explanation

Answer 2

Answer: 70,30,20

Step-by-step explanation:

The three positive numbers are in the ratio 7:3:2 .

Then largest number can be written as 7x

Smallest number as 2x

The middle number as 3x

Given that

7x+2x= 2×3x +30

9x= 6x+ 30

3x=30

x=10

Largest number= 7x= 70

Smallest number = 2x=20

Middle number =3x=30