Three prizes are to be distributed in a Quiz Contest. The value of the second prize is three fifth of the value of first prize and the value of third price is two third of the second prize ,if the total value of 3 prize are ₹14400 then value of each prize is?
Answers
Answer:
let the 1st prize be of x value....then a/to qustn 2nd=3/5x and 3rd=2/5x....so now just add all n put them equal to 14400 n u will get x=7200 now put value of x n find value of 2nd n 3rd prize...
Answer:
1st prize = ₹7200
2nd prize= ₹1440
3rd prize= ₹2880
Step-by-step explanation:
Let the 1st prize be x
2nd prize=y
and 3rd prize=z
Now we know that x+y+z=14400
We also know that y= three-fifth of x
Therefore, y=3/5 of x
=3/5 × x
y=3x/5 (i)
It is given that z= two-third the value of y
z=2/3 × y (ii)
Now, putting the value of (i) in (ii) we get:
z=2/3 × 3x/5
z=(2×3x)/(3×5)
z=6x/15 (iii)
As x+y+z= ₹14400
By putting the value of (i) and (iii) we get:
x+(3x/5)+(6x/15)= ₹14400
3x/5 + 6x/15= [(3x × 3) + 6x] / 15
=(9x+6x)/15
=15x/15
Therefore, x+15x/15= 14400
15x/15= x (15 and 15 will get cancelled)
x+x=14400
2x= ₹14400
x= 14400/2
x= ₹7200
1st prize = ₹7200
According to (i) y=3x/15
Putting the value of x in (i) we get:
y= (3×7200)/15
y= 1440
2nd prize= ₹1440
According to (iii) z=6x/15
Putting the value of x in (iii) we get:
(6 × 7200)/15= 2880= z
3rd prize= ₹2880
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