Question

Three pure inductances each of 3 H are connected as shown in figure. The equivalent inductance of this connection between points A and B is ..........choose the correct option from the given options.
(A)1 H
(B)2 H
(C)3 H
(D)9 H

Answer 1

if we use concept of short circuiting then arrange of inductors as shown in figure.
where, $L_1=L_2=L_3=3H$

you can see all the resistance are in parallel so, equivalent inductance of inductors is given by $\frac{1}{L_{eq}}=\frac{1}{L_1}+\frac{1}{L_2}+\frac{1}{L_3}$

$\frac{1}{L_{eq}}=\frac{1}{3H}+\frac{1}{3H}+\frac{1}{3H}$

Leq = 1H

hence, option (A) is correct.